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[vimeo] Use _search_regex
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@ -93,7 +93,7 @@ class VimeoIE(InfoExtractor):
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self.report_login()
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login_url = 'https://vimeo.com/log_in'
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webpage = self._download_webpage(login_url, None, False)
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token = re.search(r'xsrft: \'(.*?)\'', webpage).group(1)
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token = self._search_regex(r'xsrft: \'(.*?)\'', webpage, 'login token')
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data = compat_urllib_parse.urlencode({'email': username,
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'password': password,
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'action': 'login',
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@ -109,7 +109,7 @@ class VimeoIE(InfoExtractor):
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password = self._downloader.params.get('videopassword', None)
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if password is None:
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raise ExtractorError('This video is protected by a password, use the --video-password option')
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token = re.search(r'xsrft: \'(.*?)\'', webpage).group(1)
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token = self._search_regex(r'xsrft: \'(.*?)\'', webpage, 'login token')
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data = compat_urllib_parse.urlencode({'password': password,
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'token': token})
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# I didn't manage to use the password with https
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