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Code Issues Releases Wiki Activity

Implement a different adult sites checking algorithm

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This commit is contained in:
Filippo Valsorda 2014-01-14 16:01:00 -05:00
parent 4950f30890
commit a45ea17042
1 changed files with 32 additions and 12 deletions
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30
devscripts/check-porn.py
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@ -3,6 +3,9 @@
"""
This script employs a VERY basic heuristic ('porn' in webpage.lower()) to check
if we are not 'age_limit' tagging some porn site
A second approach implemented relies on a list of porn domains, to activate it
pass the list filename as the only argument
"""
# Allow direct execution
@ -11,9 +14,17 @@ import sys
sys.path.insert(0, os.path.dirname(os.path.dirname(os.path.abspath(__file__))))
from test.helper import get_testcases
from youtube_dl.utils import compat_urllib_parse_urlparse
from youtube_dl.utils import compat_urllib_request
if len(sys.argv) > 1:
METHOD = 'LIST'
LIST = open(sys.argv[1]).read().decode('utf8').strip()
else:
METHOD = 'EURISTIC'
for test in get_testcases():
if METHOD == 'EURISTIC':
try:
webpage = compat_urllib_request.urlopen(test['url'], timeout=10).read()
except:
@ -22,14 +33,23 @@ for test in get_testcases():
webpage = webpage.decode('utf8', 'replace')
if 'porn' in webpage.lower() and ('info_dict' not in test
or 'age_limit' not in test['info_dict']
RESULT = 'porn' in webpage.lower()
elif METHOD == 'LIST':
domain = compat_urllib_parse_urlparse(test['url']).netloc
if not domain:
print('\nFail: {0}'.format(test['name']))
continue
domain = '.'.join(domain.split('.')[-2:])
RESULT = ('.' + domain + '\n' in LIST or '\n' + domain + '\n' in LIST)
if RESULT and ('info_dict' not in test or 'age_limit' not in test['info_dict']
or test['info_dict']['age_limit'] != 18):
print('\nPotential missing age_limit check: {0}'.format(test['name']))
elif 'porn' not in webpage.lower() and ('info_dict' in test and
'age_limit' in test['info_dict'] and
test['info_dict']['age_limit'] == 18):
elif not RESULT and ('info_dict' in test and 'age_limit' in test['info_dict']
and test['info_dict']['age_limit'] == 18):
print('\nPotential false negative: {0}'.format(test['name']))
else: